Throughout this lecture, the word differentiable will be used to
mean
.
Definition 1: A diffeomorphism is a function
between open sets of
which is differentiable and has a
differentiable inverse.
Definition 2: The half-space
is the set of points in
whose last coordinate is non-negative. A k-dimensional
manifold-with-boundary is a subset
of
such that
every point
satisfies:
There is a diffeomorphism
from an open neighborhood of
such that
where the set
is either
or
The set of
which satisfy the condition with
is called the boundary of
and is denoted
If the boundary of
is empty, then
can be referred to as a
manifold.
If
, then a coordinate system
around
is a 1-1 differentiable function
for
which there is an open set
satisfying:
Proposition 1: A subset
of
is a k-dimensional
manifold if and only if every
has a coordinate system about
Proof: If
has a function
as in the definition of
manifold, then let
be the projection on the first
coordinates of
and
be defined by
Then
is a coordinate system about
. (The condition involving the
rank follows by applying the chain rule to
where
is
with
being the projection on the first
coordinates.)
Conversely, if
is a coordinate system about
, then define
by
. If
is such that
, then
is invertible in a neighborhood of
. The inverse in this neighborhood is the desired function
as in
the definition of manifold.
Note: If
and
are a coordinate systems about
, then
is a diffeomorphism as the
proof showed that
is just the first
coordinates of the
diffeomorphism
In particular,
is independent of the
choice of coordinate system
about
This set is called
the tangent space of
at
If
is a element of the
tangent space at
for every
in
, then there is a unique
in the tangent space of
at
such that
We say
is a differentiable vector field of
if each of the
are
differentiable vector fields of each
. In particular, if
is the
restriction of a differentiable vector field on some open subset
containing
,
then
restricts to a differentiable vector field on
Similarly, a differentiable k-form on
is a function
which assigns to each
an
such that
is a differentiable k-form on
for every coordinate system
about
. The derivative
of
is the differentiable
k-form on
provided by the following result:
Proposition 2: If
is a differentiable k-form on
, then
there is a unique differentiable
-form on
such that for every
coordinate system
about
, one has
Proof: For each
, let
be chosen
so that
. Let
This definition is independent of the choice of coordinate system
and
is easily shown to be the desired differentiable
-form on
Let
be a finite dimensional real vector space of dimension
and
be non-zero. Then
is non-zero for every basis
of
. Thus, the set of
(ordered) bases of
is partitioned into two sets, such that two bases are in
the same set if and only if
applied to the bases gives a real
number of the same sign. The set to which an (ordered) basis belongs is
called its orientation and is denoted
Note that
two bases being of the same orientation is independent of the choice of
The usual orientation of
is defined to
be
Suppose that for every
(where
is a k-dimensional manifold),
one has chosen
an orientation of the tangent space
. Then these
choices are said to be consistent if and only if for every
coordinate system
about
and every pair
,
one has
if and only if
Such a consistent
choice is called an orientation of
; a manifold which admits
an orientation is said to be orientable.
If the
are consistent, then one says that the coordinate system
is said to be orientation preserving
if
for every
Clearly, if
is a linear transformation
with
, then exactly one of
and
is orientation
preserving.
Now, let
be a
-dimensional manifold-with-boundary and
Then
is a
-dimensional subspace of
. There are
precisely two unit vectors perpendicular to this subspace. Choose a
coordinate system
about
in which 0 maps to
and
Then the one of the unit vectors of the form
with
is
called the outward unit normal
Suppose we have an
orientation
for
. Then choose
a basis
for
such that
. Then
the
define a consistent orientation on
called the induced orientation. Note that the orientation induced
on
from the usual orientation on
is the
usual orientation if and only if
is even.
If
is
-dimensional manifold contained in
which
admits an orientation
, then one can also define an outward unit normal
as the one such that if
is a basis of
with
, then
is the
usual orientation of
If
is a
-form on a
-dimensional manifold-with-boundary
and
is a singular
in
, we can define:
Integrals over
-chains are defined in the obvious way. In the special
case where
, we will always assume that
is the restriction
to
of a coordinate system
(where
we assume
If one has an orientation for
, we say
that the singular
-cube is orientation preserving provided that
is.
All the definitions have been set up to guarantee the following result:
Proposition 3: If
are two orientation
preserving singular
-cubes in an oriented
-dimensional manifold
and
is a
-form on
such that
outside of
, then
Proof: We have
where
and we have used the assumption that
is zero outside of
It remains to show that
But, if
, then we have
since
The result now follows by
the change of variables formula for integrals.
We can now define integrals. Let
be a k-form on an oriented
k-dimensional manifold
. Choose an open cover
of
such that for each
, there is an orientation preserving
singular
-cube
with
Let
be
a partition of unity for
subordinate to this cover. Define
where
was chosen so that
is zero outside of an compact subset
of
and
is is an orientation preserving singular
-cube
with
Then just as in Chapter 3, the value of
this integral is independent of the choice of
,
, and
.
Now suppose we have a
-dimensional manifold-with-boundary
with
orientation
. Let
be the orientation induced by
on
. Let
be an orientation-preserving
-cube in
such that
lies in
and this is the only face which
contains any interior points of
. Then
is orientation
preserving if and only
is even. In particular, if
is
a
-form on
which is zero outside of
, we have
Now
appears with coefficient
in the definition of
. So,
This explains the strange choice of signs in the definition of the induced
orientation on
Theorem 1: (Stokes' Theorem) Let
be a compact oriented
-dimensional
manifold-with-boundary and
be a
-form on
. Then
where
is oriented with the orientation induced from that of
Proof: Begin with two special cases: First assume that there is
an orientation preserving
-cube in
such that
outside of
Using our earlier Stokes' Theorem, we get
since
on
But
also
since
on
The second case is where there is an orientation-preserving singular
-cube in
such that
is the only face containing points
of
and
outside of
One has:
For the general case, choose an open cover
of
and a
partition of unity
subordinate to
such that for each
, the form
is as in one of the two cases
already considered. Since
is compact, one has a finite sum:
But then,
In
, the volume can be calculated as the integral
of the form
. We would like to find
a generalization to manifolds of this differential form.
If
is a
-dimensional manifold, then the usual inner product
on
induces an inner product on each of the tangent spaces of
. (Recall that an inner product of V is a bilinear form
such that
for all
.) With an inner product, one
can define an orthonormal basis to be one of the form
where
where
is the Kronecker
. Now, if
and
are both
orthonormal bases, then we can write
.
In particular, one calculates:
which can be expressed as a matrix equation
where
is the
matrix with entries
Taking determinants of this means that
In particular, if
where
is a vector space of dimension
, then
Proposition 4:
is constant for all
orthonormal bases of
of the same orientation.
Definition 3: Let
be an oriented
-dimensional manifold in
.
Then a
-form
on
is called a volume element if
for all orientation preserving
orthonormal bases
Example: Consider the case of 2-dimensional oriented manifolds
in
Let
be the outward normal at
. Then
define
by
By the definition of the outward normal,
is a volume element.
Further, if
is an orthonormal basis of the same orientation as
,
one has:
Also, expanding as cofactors of the last row, one gets
On
, one can compute for
using
for some
, that
Letting
, and
, we get:
Proposition 4: Let
be an oriented 2-dimensional manifold in
and let
be the unit outward normal. Then
the volume element
satisfies:
Further, on
, one has:
To calculate a surface area, we need to evaluate
for an orientation preserving singular 2-cube
. The integrand is
where
(See Problem 4.9, part e.)
Three separate results will be shown to be special cases of our Stokes' Theorem.
Theorem 2: (Green's Theorem) Let
be a
compact 2-dimensional manifold-with-boundary. Suppose that
are differentiable. Then
Proof: This is just Stoke's Theorem in the case of a 1-form.
Theorem 3: (Divergence Theorem) Let
be
a compact 3-dimensional manifold-with-boundary and
be the unit outward
normal on
. Let
be a differentiable vector field on
Then
In terms of
, this amounts to:
Proof: Define
Then
Further, Proposition 4 says that:
So, we see that this is also a special case of Stokes' Theorem
Theorem 4: (Stokes' Theorem) Let
be a
compact oriented 2-dimensional manifold-with-boundary and
be the unit
outward normal on
determined by the orientation on
. Let
have the induced orientation. Let
be the vector field on
with
and
be a differentiable vector field in an open set
containing
. Then
In terms of
, this amounts to:
Proof: Let
on
be defined by
Again, using Proposition 4, we get:
Since
, one has
as one can see by evaluating each equation at
.
It follows that
So, this is also a special case of our earlier Stokes' Theorem.